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16x^2-44x+28=0
a = 16; b = -44; c = +28;
Δ = b2-4ac
Δ = -442-4·16·28
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-12}{2*16}=\frac{32}{32} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+12}{2*16}=\frac{56}{32} =1+3/4 $
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